-3250=-16x^2

Solution for -3250=-16x^2 equation:

-3250=-16x^2

We move all terms to the left:

-3250-(-16x^2)=0

We get rid of parentheses

16x^2-3250=0

a = 16; b = 0; c = -3250;
Δ = b2-4ac
Δ = 02-4·16·(-3250)
Δ = 208000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{208000}=\sqrt{1600*130}=\sqrt{1600}*\sqrt{130}=40\sqrt{130}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{130}}{2*16}=\frac{0-40\sqrt{130}}{32}
=-\frac{40\sqrt{130}}{32}
=-\frac{5\sqrt{130}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{130}}{2*16}=\frac{0+40\sqrt{130}}{32}
=\frac{40\sqrt{130}}{32}
=\frac{5\sqrt{130}}{4}
$